And if you were to add all of these together, how many fifths do you have?

For situation calculus it turns out to be easier to do it the other way around.

What is it that they have been doing and where are they now? Vukosi Marivate, Graduate Student, Rutgers University

The scales would be tipped to the right. It's not in P. We're looking good so far.

Not a scratch.

Can you imagine which of the three lines would be described for this equation.

I think you can figure out which one it is.

And here we can use a tool called a quadratic equation.

So zero session is going to cost me 20. That is that point over there.

And from this alternate 3 there's this 1 6 3 loop that connects to the main loop at 1, which is the same 1 as 1 has always been.

So now we can see the methods and attributes on our P object, and we can see a couple of them that are probably interesting to us headers, for one, and get url is another.

We're taking 2 3 of the 4 5.

And we want to take 4 5 of this section here.

Then we go and compare the states.

letters and five letters and so on.

So what pixel should be aligned with the black pixel over here?

Is r is going to be 1, r going to be 3, r going to be 2, or is r going to be 0.

Is it this or this or this or is it this? Choose whichever one seems to fit best.

And what are three ones?

Do me just one favor

In fact, when I started teaching this course, in Unit 1 I was trying to think of a website that was 100 static, and I can't think of one.

Is the function shown here admissible or not?

At least one resource agent has been found.

He's from a...

This is another big piece right here, another one, another one, and another one.

Well what's the probability of you picking right the first time?

Just for clarity, party A is depicted in red and party B in blue.

And each of these can vary by country.

That's really, really, really short.

For a real web crawler, this is a big challenge.

So to go through an example, let's say we have this finite state machine.

That is the thousands place.

Tell me, you don't want one yourself, no?

How many ways to get here?

So this really is very explicitly what we were doing by hand, just one piece at a time.

Will orientation or heading never play a role?

All those windows out there, I'm behind one of them

So we are going to subtract the yellow from the green.

We're going to take one 1 from the 9, so let's do that.

These particles together comprise our estimation after the motion command over here.

Five squares, subtract four squares equals one square, one twentieth.

And our slope is negative 1.

You'll get one anyway!

So that's two.

So for option one, we have a list, and it's a single list containing strings.