So you're going to get some combination of the i and j unit vectors.

3 minus nothing is 3.

And now I evaluate this at 1 and 0.

let's just divide by a again.

So this was c plud d i, so this is its conjugate.

And so, if we just put this on the other side of the equation, what do we get?

Transform of any arbitrary function very, very quickly.

Here we go the other way.

Got it.

If I multiplied this area times a small dy, then all of a sudden I have a sliver of volume.

If you distribute the negative 3, you're going to get that expression.

So, minus 2 3 x, you go down 2 for every 3 that you go out.

We'd also want to multiply the right hand side by x.

You multiply that times negative 8

Someone has to say, well, when x is 2, y is 3.

And then you'd get x could be equal to negative 8, or x could be equal to negative 10.

And if x plus 6 is 0, then that means that x is negative 6.

There, we just set up a equation with one unknown and we can solve for x.

13 00 00 42,55 gt 00 00 46,34 Now, all this is saying is what value does the expression x squared approach as x approaches 2?

So now we just solve for x.

Or the probability of getting heads, tails, right?

In 2004, if we assume the pattern continues, let's add another 75.

You give me any x, any y, you give any x, y in the x y plane, and these are going to end up with some numbers, right?

And it contributes to about 70 samples of those thousand samples.

Next was this trial.

This term comes from the x times the x.

We have AC and DC, get 12 volts DC, so that could be used for certain applications.

And then we distribute again.

We have a surplus to sell in the market.

We multiply the denominators 3 times 2 is 6.

So let's subtract.

So you get 10 billion for them.

And what do we get?

So plus another 4 centimeters.

We can derive great pleasure from books.

look, I have a length of 2 meters. So I'm going to have 2 groups of 3.

Narrator

And for the first time, we can actually do that.

Those are very valuable.

Plus 1 s that's this right there times the Laplace transform of 1.

This is Brad doing one of the Ekman FACS poses.

So what we have here is a function of y that gives us an x, which is exactly what we wanted.

If you want, you can just multiply this guy out and you'll get that right there.

So this first term here, the upper left term, where does it get its row information from and where does it get its column information from?

Is greater than 3 minus 7 which is negative 4.