Let me put the Laplace transform of and I'm also going to the sides.

All right.

Supersede

Now, since we want to apply this to an integral, maybe

And if you replace this expression everywhere, where you see an x, right?

Now, we compare the number of 6s with the number of 5s, and there aren't enough.

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Simple game quest.

Laplace transform of e to the at.

And we got g of 3 equals 7.

That means the heap property isn't satisfied but all we have to do to fix it is we just swap the value in the left child and i.

Do you want to replace it?

Or, we could say, let me just write it the other way.

The chain rule, derivative of cosine is minus sign.

This is equal to 3 times 5, 3 times 5.

For the support vector machine what we are going to do is essentially take this, and replace this with cost 1 of z, that is cost 1 of theta transpose x.

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This expression is just another way of writing this expression.

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And now we can use this, which we proved several videos ago, to resubstitute it and get it in terms of the Laplace

You just get a 1.

So what is this equal to?

And so we get c2 is equal to 5 2.

let's substitute 42 into our original equation

We have 7 minus 10 5.

Everywhere that we saw an x, we will now replace it with a z.

But we could put an x in here.

That is the same as saying that the old salary was the new salary minus 10,000.

Using what I described in the previous slide what we're just talking about, you can actually patch this up by moving the 50 around doing some various swaps.

And the worst thing? It's all done in secret.

Do you really want to supersede this article?

So C is equal to 6.

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But we can figure out what h of 10 is pretty easily.

And now, if we wanted this in terms of x.

So let's make v prime is f prime, and let's make u e to the minus st.

Well you go back to the definition.

What that means because there's a little triangle here and we're trying see whether or not it's 3 colorable.

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In each square, we calculate the average color.

Right?