But if you cross this row and this column out, you're just

So we have that green color, right?

We multiply these 2 things.

We're going to take one 1 from the 9, so let's do that.

What numbers do I have left?

Or I could say, here are all the scenarios where I roll a 1 on the second die.

So this will become one whole and 1 2 left over.

And over here, we have nine things with a mass of one kilogram, which we could write as 1 1 1 1 1 1 1 1 1.

So I could have the matrix 1.

Then when we go to row 1, column 2, I want the determinant of 0, 1, 1, 1.

So what we do is we write the 6 in the 1's place and we carry the 1.

So if you cross out the row and the column, it's this determinant.

look at the whole number parts.

So for example, this 1, 1 position, row 1, column 1.

This 1 and this 2, that's this 1 and this 2, this 1 and this 2.

So now, when we're in row 2, column 1, we cross out row 2, cross out column 1.

The max of 1 is 1, so this would also get an evaluation of 1.

We said what if we took a third of these things?

I don't know if that helps you or not.

They're independent events.

So let me graph it...

5 times 4 is 20.

We could either say, OK, if we look at actually,

Let me put commas here so it doesn't look like eleven.

So now this is 1 8.

So you get fifty five.

So let's just see what they have here.

The 0 becomes a 10 because we got this 1 right here.

If I were to draw it on a number line right here, that is 0, that is 2 and 1 2, and that is negative 2 and 1 2.

I can rewrite this as the sum of this 1 represents 1 1 10,

This can be written as one quarter subtract one fifth.

So let me say out of this area I don't know this is 1 2.

If I were to take my original matrix, and I were to cross out this position's row and column.

You see how on the bottom two problems I had two different signs, positive 1 and negative 1?

My matrix is going to be 1111 times, and I'm going to write down the sizes of my four houses here and

So a, nice deep a, plus bolded b is equal to, I just add up each of those terms.

I'm gonna add that point on the surface.

I really encourage you to play with this and explore the excel formulas and everything.

You have a remainder of 1.

You have three of the eighteenths left over.

Why?

We're only looking at the maxes.

Or let me not even assign them.

So we could also write... ...we could also write 12... 12 groups and in each 1, I have 1.

Martin Bedell number one.