So.

We either just multiply both sides by one five, or you could just do that as dividing by five.

Maybe I'll circle that one, I could have circled that one.

We want the right side to just be x minus 1.

Also you could take use INT the INT function which will convert that string into an integer.

Let me do that.

So let's do both situations.

You can divide the numerator and the denominator by 9.

So these are just constants from an x point of view, so this is all going to be 0.

Chance, the flip of the coin, doesn't get the choice of one direction or the other.

You'd have a positive number of x's on the right hand side.

So that would be 3x squared plus 1.

And so we have 2y times 2y minus 3, plus 5 times 2y minus 3.

Now, what if I were to ask you, is there an x and y pair that satisfies both of these equations?

Sal Let's check our answer.

Or you could say if x is great well, you could go both ways in that.

They both have one 5 that's one 5, one 5.

The absolute value of negative 11 is 11, so we get 11 is equal to 11, so they BOTH work.

This isn't any kind of fancy factoring.

So one way to solve these systems of equations is to graph both lines, both equations, and then look at their intersection.

We have x squared on both sides of this, we subtract x squared from both sides of the equation.

No, I want both.

And I could isolate the y on either the left side or the right side of the equation.

And then to solve for a, we just take the square root of both sides, the principal square root, the positive square root of both sides of this equation.

My parents are both dead.

Both of my parents are dead.

Both of my parents have passed away.

Do they both understand Japanese?

Well, you look at it here, it's going to be this point.

These two guys clearly have some common factors.

You can just keep going below 40.

Remove the bitter white pith with the tip of the knife.

And if x minus 7 squared is equal to 0, take the square root of both sides.

That looks like that.

So they both deserve at least a price to earnings of 10.

So if you can divide all of the terms by 9, it won't change the equation.

And the 8 over 2 that's a 4 we do that first.

It's divisible by 3, so it's not that.

They'll say 'No, you can't go that way.' They're gonna close up. They won't allow blood to go that way.

And then, let's see, I want to get rid of this minus, and I want to get rid of this b squared.

Our torpedo and theirs.

The first way is, I think, on some level, the simpler way.

We're doing this case right here.

Cao Cao likes to play this game, both with friends and with foes

Let's do the same thing for 6 9.