Superquadric ellipsoid

Superquadric Ellipsoid

superquadric ellipsoid

2x squared.

Again, there's variance in the population, sigma squared.

We only have 1x squared terms, so let's write that down.

Look what's in the numerator, sum of cross products.

Can you spot me a 20?

OK, now we can simplify.

Lynn example.

I swapped the sides.

Arthur Benjamin

AB 23 squared, OK. Audience

So the standard deviation is one half and the variance sigma squared would therefore be the square of 0.5 would be 0.25.

So we put in one density.

AB 987 squared is 974,169.

57,683 squared.

The taxi picked up two passengers.

He has no less than two thousand yen with him.

It's going to look like that.

Because I told you at the beginning that if you wanted to find the so if you have an ellipse so if you have this is an ellipse, x squared over a squared plus y squared over b squared is equal to 1, we learned that the that's over b squared this is an ellipse.

This gives me the multi, the element wise squaring of

I'll assume that these events are independent.

And I think you're familiar with what that looks like.

Minus 2 and minus 2 is minus 4.

The balance at the bank stands at two million yen.

The general form of an equation, or the general equation for a circle, is x squared plus y squared is equal to r squared, where r is the radius of the circle.

Well this is a plus here, so the parenthesis really don't matter.

Again his average 22.7, standard deviation of 9.6, and variance of 92.

I'm think about standard deviations, but the formula on the previous 5 actually gave the estimates of the squares of theses things, so sigma squared 1 and sigma squared 2.

So 15 squared plus 20 squared is going to be equal to r squared.

I sold the picture for 20,000 yen.

The same properties. The same viscosity.

So let's take the x squared terms first.

And their sum is equal to this up here.

10 for v.

So that's equal to 25.

Or we could write this as x minus 7 squared is equal to 0.

I'm going to break the problem down into three parts.

So it's x squared over a squared plus y squared over b squared is equal to 1.

Of theta one x I minus y I and if you simplify this turns out to be. That. Zero

And now we distribute this minus over this whole expression.

So, sigma squared 1 of course would be equal to 4, for example, as the square of 2.

We don't do that. But I did it here just to demonstrate the similarity of some cross products.

So let's substitute that here.