And what we calculated here is just the average slope across this change in time.

B goes straight up and down, so we can add up arbitrary multiples of b to that.

So c1 is equal to x1.

We said this could be any constant and this could be any constant.

I hope that doesn't confuse you.

2 is just one little point in R.

Now my claim was that I can represent any point.

PROBLEM Construct a line perpendicular to the given line.

There you go.

This is minus 4 times our vector v.

Any number squared is just that number times itself.

Well, and you could look at this visually

And it's often used as the definition of an ellipse is, if you take any point on this ellipse, and measure its distance to each of these two points.

What does vector b do?

But the convention for vectors is that you can start at any point.

This goes there. This matches that part.

So this function definition really should say f of x is equal to x squared minus 5 for x is equal to we could write any member for x is a member of the set minus 2, minus 1, 0, 1, 2.

Any

Looks like a reversed check mark.

So let me take another arbitrary point on this ellipse.

So let's say that you're starting at the point x1, and x2.

If we want to say there's no dirt in any location, it's a little bit more complicated.

I could draw it like that as well, but let's just say this is set R.

Random engine

Random colors

Random Lamp Style

Any files

Any kind of value

Jeeves, Mr. Bickersteth is still up the pole.

Any raccoon.

So let's think about it.

Minus 5 comma 6 Is right there, so I draw my vector like that.

If you say, OK, what combination of a and b can get me to the point let's say I want to get to the point let me go back up here.

Let's say we're dealing with two dimensional vectors.

So we could, say, we could add vector b to it.

So, the first thing we realize, all of a sudden is that no matter where we go, it was easy to do it with these points.

Six random colors

Two random colors

Random text alignment

anything

What does that have to do with regression going backwards?

Any value

So this number right here is going to be the exact same thing as if I took a point right here and I'm picking these points arbitrarily, as long as they're on the hyperbola, and if I called these two points d3 and d4, the difference between d1 and d2 is the same thing as the difference, between d3 minus d4.

The second system detects any increase in temperature.

I could do 3 times a.