What was our original problem that we started working with?

Look at this closely and notice that that is the same hopefully it's the same as our original problem.

NP hard and therefore a polynomial time solution for that problem solves everything in NP.

We can go from that cube to that cube.

And once we had the answer to that, we need to multiply that by 2 to get the answer to the original problem.

OK.

We basically have solved problem Y by bringing to to bear our solution to problem X, or to say it another way, problem Y has been reduced to problem X.

Where do we stand today in the field of computer vision in 2012? If you consider the area of recognition.

And we set the parameter theta zero to be only zero. In the next video.

Hometown security means creating wealth here at home, instead of destroying it overseas.

Well, it's going to give us what a minus 1 times b is, which is a times b minus b.

Catalan and Spanish.

So we just add the b back in and we should be done.

Oh, we're doing fine. Yeah, we're doing great. Two little peas in a pod.

And that's choice B.

With that said, let me erase that and go back to our original problem.

So the inequality stays the same as in our original problem.

So it's choice B.

Listen, we've got a problem, a DEA problem.

Even though moving one over here and one over there would give a better solution.

So there were six ways to get to this cube right there, from that one.

And the answer is yes and no it's deeper than all of that.

We actually never even have to evaluate this integral.

Or do I have something wrong with the equipment?

My next question pertains to the tracking problem that we talked about in class.

That bad spirit made biggest trouble of all.

So what did we do here?

But yes, it's also true that the Internet has problems, very serious problems, problems with security and problems with privacy.

And the romantic language is bound to create lots of problems.

The birth rate is not the only problem we're facing.

Now that we've talked about reduction, we can revisit that definition and say a problem X is NP hard if we can reduce some other NP hard problem to it, what that really means is we can use a solution to problem X to solve some NP hard problem, that means that solving X has to be at least as hard as the NP hard problem making it therefore NP hard.

It either stays the same or gets bigger.

Network problem

Multisession Problem

Parser problem

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And that's choice C.

The other one would have been if you had a minus sign here.

That's what the y intercept is.

So the answer was A.

Anyway, I like that problem.