I was not formal.

All right, I hope you can read this.

lifetime value needs to be greater than customer acquisition cost.

I think you get the idea.

I would say a lot easier than what we did in the previous first order homogeneous difference equations, or the exact equations.

Well, we have to add in a moderator variable and a, what I'm going to call a product term.

And, and I agree with you right now.

Now... (Laughter)

So the easiest way to approximate it is to say, well, the simplest polynomial is just a constant, right?

How do I get there? Well, let's apply Bayes rule.

So again, minimize sums of squares residuals, just like in simple regression.

Less meat, less junk, more plants.

So it becomes 8y²

That's just what we were going for.

Problem 40.

Extremism.

It's a formality.

For what value or values of x is y equal to 0?

So this equation right here at first it doesn't look like a straightforward linear equation

In the early universe, we know that it's very close to the critical matter dominated universe. Matter or radiation.

Y will always be less extreme.

So essentially they just want us to solve this equation.

It's just taking away five things.

The distance to the galaxy, Hubble constant and it's peculiar velocity.

And watch the previous video just to see why this characteristic equation works.

So if I say that 3X 2 is less than or equal to 1

Going to the logarithm, we replace it with a sum that is 6.

Then simplify the expression.

We did not use the distributive law just now.

This vertical bar means I match either the thing on the left or the thing on the right.

Let me do this, let me draw this last circle

The vibe wasn't right?

We know our focal length f, and I care about our depth z.

Keeping ambiguity in mind, if this were a Python or JavaScript or even just on the whiteboard or on a piece of paper in mathematics, this is a mathematical expression.

So in the event where x plus 2 is less than 0, we can just say that x has to be less than minus 2.

So 4j minus 100 I just added all the constant terms has to be less than or equal to 500.

So let's just write this all out.

This is our SSD value, our sum of square difference value.

So let's just get the absolute value of h on one side of the equation.

So now, we know how to find the 0's when the the actual equation is easy to factor.

Either of these would work as the test condition for our loop.

It equals minus 1.

Easy won't be part of the equation.

Now before we go on, in the next one I'll show you some fairly straightforward differential equations to solve.

Straightforward enough.