Same questions, same answers.

So let's say I had f of x is equal to 1 over x squared.

That's my story, and it ain't gonna change.

It won't change my mind, I'm sorry.

And they said, Well, one is elegant, the other one's glamorous.

Now I will interact.

Add to the imaginary parts you have 5 i minus 6 i. You get negative i

But with the differences due to having not quite the right policy,

You could try all of these out.

Anything?

Is that what you told Tom Riddle, when he came asking questions?

And you end up with 12 stars.

And you evaluate that from 0 to 1.

And the denominator would be 5 times 1, which is equal to 5.

But at the end when you simplify it, you'll get the exact same answer.

You can be pissed at me all you want. it's not gonna change anything.

The general idea is whatever order someone asks you for the different items, you put the ratio is going to be in that same exact order.

Thought any more, meaning reconsidered? No.

And that's where we're getting a lot of our mileage from. Let's actually analyze this algorithm.

This constant in front of the n² is not going to matter in Big Theta world, because we can go above it or below it.

You get to negative 90.

Look, do the math, Marie. It only comes out one way.

So 1 minus nothing is 1, and you get 12.

Okay, what about the FBl?

And just like we expected, we got the same thing.

Let me do a third quiz this coin was flipped seven times and it came up tails every single time.

So 45 n.

It's zero for any other number.

That's 7 times 5, and so is this.

We'll learn in a second what we do when the denominators are different.

You can say either of these could be equal to 0, but they're the same thing.

And just like that.

This problem becomes 25 divided into 103.075.

Can you switch the two numbers and get the same answer?

What? I got to go through these twice?

Are you asking if we're the type of twins and things like that? No.

This is the one for the variance.

1 4 times 8x is 2x, plus 1 4 times 12 is 3.

Acknowledge by same encryption protocol.

You spoke at the same time I did just then.

Who is responsible for equality?

We get the exact same thing as if we multiplied 3 times 3, if we multiplied the length times the width in meters.

Remember, we can only do optimizations that don't change the meaning of the program.

So you're left with 10uv times the quantity 2u minus v.

They're not the same. The top one is 10 percent longer than the bottom one.