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This is equal to the integral from 0 to infinity.

We get I is equal to p 2w over 2.

Let me write that.

So let's do a general form.

Over thirteen.

And then we multiply that times dy dx.

9 is the same thing as 3 squared.

An idea can transform the world, and rewrite all the rules.

The artist, Joseph Beuys, wrote a new formula

8 minus k times 5 factorial.

Now we have to factor this.

But they don't have that.

We'll write twenty dollars in purple.

So this is 4 hundreds and 3 tens.

How about PR?

So we can rewrite this up here.

So that would have been a horrible mistake.

Let's take the constants out first.

It's equal to some function of x and y.

Find the value of 5 to the third power.

So times the magnitude of the displacement.

It'll break up the 13x into I'm going to write the 8x first.

And so with that in mind, I can swap the order here.

The total number of outcomes is 2 to the eighth.

So I'm going to go with 3 times 10 to the fourth.

2 doesn't go into 1, so that's just the remainder.

We solved this thing.

UI Rewrite, lots of code cleanups and fixes

So let's try to complete the square with it.

It's a mapping from R2 to R, but this always equals 2.

So negative 15 times negative 1, well that's the same thing as positive 15.

So this is equal to 61 20.

We're almost done.

Actually, if we distribute a 9x.

Minus 37 plus 40, that's plus 3.

We normally think of things like 1 2 3, but the lowly 1 alone is in this grammar.

And we know that that's the same thing as well, because we know this is onex, x is the same thing is onex.

So we have 2 times 2 there, or 4 there, which is a perfect square.

Well, one way to view this is to think about the parse tree, which I've kind of drawn here upside down.

Let's say that our grammar has some special start symbol S.

Think about it for yourself.

And we're going to substitute v for y over x, but we're also going to have to substitute dy over dx.

So let's just shift this circle.