Remember that c was the 0th element of cd.

Well, let's just do this the fast way.

Shift

Shift

So when you take something to the negative times 10 to the negative power, you shift the decimal to the left.

Now we want to take everything jstate had after the dot, except we want to remove the x, because we shifted the red dot over it.

And then I'll do another video where I actually shift the hyperbola.

left, and you would have to add another 0.

Shift left

Shift up

Shift down

Shift right

Hatcher's got you working a double shift?

SHIFT and Enter! SHIFT and Enter!

(Typing noise) (Typing noise)

Every time you multiply it by 10, you shift the decimal to the right by 1.

So this is equal to 74,000.

This is the Laplace transform of e to the and what's a? a is what we shifted by.

It's scaled up.

Your shift's over.

Your shift is over.

You do x squared plus 1.

Laplace transform of, and this one here?

Yes? The new man here worked the night shift.

One out of every three, every other cycle.

So I'm going to draw two lines with these slopes, with positive 1 2 and negative 1 2 slopes, but they're going to be centered at this point.

But instead of its vertex, or its center or its starting point, or whatever you want to call it, to be at the origin, it's shifted now.

And so essentially, it will shift, it will change the entire demand curve.

If, on the other hand, the dot is right before a terminal, a token a fixed part of the input we shift over it.

What if there's no (c) and there's no (d), and we've reached the end?

So chart 1 had a dot in front of a big (Q).

And then let's have the square root of x plus 4.

(Applause)

It might be a little non intuitive that you say minus 4 to shift to the right and plus 2 to shift to the left.

And we established this was our f of t, so we just shifted it by c.

I have an e here.

So 3.102 times 10 to the second power is the same thing as if I shift the decimal point 1, and then 2, because this is 10 to the second power it's same thing as 310.2.

Notice it did exactly what I said. x minus 4 squared was shifted four to the right. x plus 2 squared, was shifted two to the left.

And that's a bit magical for now, but we'll see why we want to do it, real shortly.

So it's shifting demand to the right.

You rescheduled your rotation. I almost missed you.

We're going to return a new parsing state that still has x at the front, but now instead of ab it should have abc, because we're shifting the red dot one.

If U equals 1, all the values are cyclically shifted to the right by 1.

It's not just about terrorism, though.

I suspect he was late for his duty shift.