He hung a picture on the wall.

I hung a picture on the wall.

Hang that picture on the wall.

My brother hung the picture upside down.

Put these pictures up us for wall, please.

She hung a little Picasso on the wall of the drawing room.

You could say that the work is equal to 5 newtons times, I'll just write a dot for times.

And do you have the accompanying guilt?

The time is 5 times 10 to the second seconds.

But of course, we're doing the chain rule.

I wonder where to hang the picture he gave me.

To get that x plus one out of the denominator, we multiply both sides of this equation times x plus one over one times this side.

And that makes sense because two to the three is two multiplying by itself three times, to the fifth is two multiplying by itself five times, and then we're multiplying the two, so we're going to multiply two eight times.

You can say x plus five over one.

There is a picture on the wall.

And that sum I'm going to define as a times s.

Is it practical?

If it's false, then the flag hit will valuate to zero, 1 hit will be 1.

And then the denominator will have the b.

So in this case, n factorial was 7.

And the denominator would have been 2 times 2 times 2 (that's what 2 to the third power is) 2 times 2 times 2 times 5 times 5

I'm just going to do minus a positive 3 times each of these.

I'm gonna call you back.

Wherever we want to go, we could go arbitrarily we could scale a up by some arbitrary value.

And, of course, the whole time you have that 5 sitting outside.

So just to get the math here, so to get to this number right here, we just multiplied.

But we can't just multiply one of the terms by x.

Two to the third is two times two times two, right?

This is the delta function shifted to c.

The height is the value of the function, which is x y squared.

The picture is hung crooked.

There is a Picasso on the wall.

Oh, actually, I made a mistake. y over x is equal to the natural log of x plus c.

And then to get to a cubed, what did we do?

And then to get to a to the fourth, what did we do?

Thank you.

Now, what's great about this is, there's no trickery here.

I hung my hat on the peg.

What is that going to look like? e to the minus st times f of t?

And in fact, here we've got a lazy person on a bed sleeping.

We can multiply both sides of this equation by x plus two over one. x plus two.

So this is the first step.

So I'm almost there.

P i times the normalizer times the Gaussian expression.

And set a trap, and kill those who come.