You can be as precise with SketchUp as you'd like.

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There's a real good case to be made here.

We can actually simplify it because 9, 3, and minus 18 are all divisible by 3.

This one over here we added up all the digits and got 18, 18 is divisible by 9.

Another way you could think about it, you have to be divisible by both 2 and 5 to be divisible by 10.

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So here we're divisible by 2 and 3, so we're going to be divisible by 6.

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And you might see where all of this is going. This orange stuff here, is this divisible by nine?

Well 405, 4 plus 0 plus 5 is 9, so that is divisible by 9.

So anything this multiplying this by divisible of nine.

This standard is called ASCIl the American Standard Code for Information Interchange.

That is 12 times 3.

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Are they assigned to individuals?

Not all of them are divisible by either r or s.

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Now, to be divisible by 6, you have to be divisible by 2 and 3.

So if you take the digits 2 plus 5, you get 7.

And again, it comes up with a number of interesting inputs.

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Let's divide the denominator by 2.

So 27 divided by negative 12, well, they're both divisible by 3.

Lets move on to 2.

So the first one, that's maybe obvious.

So you're going to have, the 2's are going to cancel out, the 5's are going to cancel out your just going to have a 3 leftover, so it's clearly divisible by 20 and if you were to divide it by 12, you'd divide it by 2 times 2 times 3 this is the same thing as 12 and so these guys would cancel out, and you would just have a 5 leftover so it's clearly divisible by both, and this number right here is 60 it's 4 times 3, which is 12, times 5.

All numbers, and this is just one of the examples,

I've rationed it.

So clearly any natural number is divisible by 1 and itself.

Two plus seven is nine.

1 2 is equal to 3.

You do have a zero in the ones place here.

Then if you move to 10, 10 is also not prime, divisible by 2 and 5.

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If you add two things that are divisible by 3 the whole thing is going to be divisible by 3

If your job is to dance, do your dance.

So 19 is not divisible by 3.

So it's prime factorization needs to have a 2 times a 2 times a 3 in it any number that's divisible by 12