France is adjacent to Spain.

We now know that this is the final distance and then we delete that from the dist so far structure.

You can try computing when a graph is all connected. You put the neighbors on a list, the open list.

These glial cells become activated.

And then I apply the formula.

So given a node v or computing the clustering coefficient involves

Germany borders on France.

Joins adjacent cells when they are in the same row.

Okay, well, let's go to j and do a mark_component from j.

We're going to average it for the n nodes in the graph.

h shares borders with g and e and d . gcde

f shares borders with g , b , and a

Let me expand the first one. This one over here.

So, we start up v. We mark v.

And that is exactly what we found.

The first law is two colorability.

So Kv which is the number of neighbors is 4.

It actually kind of matters, but zero seems like a reasonable choice.

The two villages adjoin each other.

And it can actually be all the way to one if we have a cleek.

We have to go back to the beginning and do it again.

So it's not that tightly connected and in fact you know that sort of what we saw as well that V is connected to a bunch of neighbors but they are not really connected to each other all that much.

We mark A as visited and we add it to the open list.

We make sure that we select our equipment properly.

In the neighbouring room on the left a painful stillness descended.

There's really no choice. It's the node over here.

Letter C, B, and D then we choose one of these nodes,

E is already in there but we can add in F at the tree edge.

Then we go through its neighbors.

We've got this one, and this one, and this one, and this one.

This is the matrix of cofactors.

Take g off the open list, its neighbors are all already done, nothing is added.

So in this case, it's a little bit of a quarter, which is pretty clumpy.

No, said Gregor.

If you look at any node in the left side say the middle one.

In particular, we're going to make each region on the map correspond to a node on the graph and we're going to connect two nodes on the graph if they share a border and therefore can't have the same color on the map. a shares a border with b and f

Then what we're going to do is we're going to count up the number of links between these neighboring nodes.

And our instructions again say that we look at all the neighbors of v, w and z.

We take the ending little piece off the to do list and say Oh, q that's what we have to do.

In this case, we've got Seattle, Los Angeles, Dallas Forth Worth, not Atlanta but Pittsburgh.

The embassy is located next to the Supreme Court.

Yes, there is. There is still one more thing on the to do list.

And for each pair of neighbors, it does a calculation to compute how connected it is and then returns a measure of how densely connected the neighbors are.

Then what we do is we recursively go and mark all the things connected to that node, count up how many things got marked in that way, and then we return.

Flood fill Fill adjoining pixels with the same color with the current color