Now we just do the same thing over.

How many times does x minus 2 go into 2x squared minus 8?

lambda, such as if lambda were equal to 0.

So the first step is you say, OK, the highest degree term is 2x.

I think you see what we're doing.

Right Move to the next control

We have an x squared term.

It's classified.

And now we've cleaned up the equation a good bit.

That's because I've fit my parameters to the test set.

So they give us a function, f of x.

So let's add our x terms.

Also on the web, when you're filling in one of these forms like your addresses,

So the first term gives me 0.8 times 0.2 times 0.2 times 0.5.

Is it Θ of itself? Is it Θ of the term with the largest coefficient?

So when you see something like this, when the coefficient on the x squared term, or the leading coefficient on this quadratic is a 1, you can just say, all right, what two numbers add up to this coefficient right here?

Poly

Plus, and what's the derivative of a next term, of a first degree term?

4 minus 1 is 3.

Let's do another one like this.

So let me just draw a little bit of a graph.

Consider the following graph where the horizontal axis graphs complexity of the solution.

But before we even do that, let's see if there's a common factor across all of these terms, and maybe we can get a 1 coefficient, out there.

So you get x minus 2 goes into x to the third and actually, what I'm going to do is, I'm going to write I leave space for the second degree term, which is 0, the first degree term, and then minus 8 is the constant term, so minus 8 I

So 2x squared.

You want to split the first degree term into two terms.

So this first degree so this is going to be a 0 degree or a constant term Here the degree is 2.

But just as a reminder, what you want to do is you want to split this middle term.

Next player's height

Higher level functions.

If the document has a table of contents, clicking on a table of contents item will bring the document to the page linked to that item.

So what's the first derivative of p? p prime of x is equal to, well, the derivative of a constant term is 0, right?

No, my brougham is waiting.

Let's say I'm defining, so this is a polynomial.

This is now a constant term, that becomes nothing.

Now let's consider the model selection problem.

Let's start with the training error.

So x is equal to r3.

whereas we're here on the right of the horizontal axis, I have much larger values of these of a much higher degree polynomial, and so here that is going to correspond to fitting much more complex functions to your training set.

I've written out our Abstract Syntax Tree for (X) 2.

On one hand we want something we can actually reason about.

So let's see if we can make some headway on this.

I'll put them on the right hand side.

The next gig is gonna be dynamite!

Now for the part you like best.