" P で"の翻訳 英語に:


  例 (レビューされていない外部ソース)

p 1 p p ( 2p) 2p 2 p p 2 p 3
And then this term over here, this whole thing over here, is going to be plus p times 1 is p. p times negative 2p is negative 2p squared.
P P とPー
Once again, based on this P, I'm going to start bringing in rules 1 and 2.
p掛ける (p p)の1と p 2 pp p (1 p) 綺麗な式にまとまりました
And if you want to factor a p out of this, this is going to be equal to p times, if you take p divided p you get a 1, p square divided by p is p.
p 1はp
So that cancels out.
0 pは p
So this is going to be equal to 1 minus p.
P Q P Q P Q Q P
And the sentences are P or not P, P and not P,
P P
Let's say that this is our grammar
P X3 X₁ P A X₁ P X3 X₁ A P A X₁ す これが全確率
P of X3 given X1 is the sum of P of X3 given X1 and A times P of A given X1 plus the A complement, which is X3, conditional X1 and not A times P of not A given X1.
ここは p オフす p
In these other examples we were picking 30 percent, but now we can say it's p, it's the percentage off.
P. T. P
F, L, E, P, T, P L, E, P, F, L, F, L, E, P, T, P, L, F, E, T.
A P P
APPLE.
P(A) Ʃ P(A B) P(B)
Now in probability terms, people often write it as follows
P H R はP H R S P S
Let me just do this over here.
S P P P またPが何もなしと 書き換えられるPythonコード
It's that grammar of balanced parentheses.
P P または
So chart state 0 includes the following parse states
ピンクの p を得るこの p プラス p 以上 1 プラス プラス
Now let's add that pink p to both sides of this equation.
よって 分散はp (1 p)
So p times 1 minus p, which is a pretty neat, clean formula.
Pは P を得たあと2つ目のルールPを消します
The first one looks pretty good. I just apply rule 1.
P 51
Those are P51s.
それぞれの値から算出きます P H S R P S R P H S R P S R
P of happiness given S and R times P of S and R, which is of course the product of those 2 because they are independent, plus P of happiness given not S R, probability of not as R plus P of H given S and not R times the probability of P of S and not R plus the last case,
P P とあります
Another way to think about that is let's say that we're in a particular state like this one
P A B P B A P A P B となります P B A を尤度 ゆうど と言います
P of A given B where B is the evidence and A is the variable we care about is P of B given A times P of A over P of B.
残り2つはP B A とP B A
It takes 1 parameter to specify P of A from which we can derive P of not A.
次はp軌道 p軌道はダンベル型すね
So let's say that that's the nucleus and I'll just draw their p orbitals.
P 2 C
So, I can rewrite this thing over here as follows
P
P
p.
p.
P .
What's next?
P ...
P .
P ...?
P ... P ...?
P ...?
Teacup!
P
Similarly, over here I'm going to apply rule one three times.
P...
P...
あい行くぞE, F, L, E, P, T . P, L, E, P, F, L, E L, E, P, T, L, P, E, F, E, T, Z, E, T.
All right. E, F, L, E, P, T P, L, E, P, F, L, E L, E, P, T, L, P, E, F, E, T, Z, E, T...
P A は事前確率 P B は周辺尤度
This expression is called the likelihood.
Pが左にあるのPがタプルの0番目になり P が右側にあるの
The second element corresponds to my second grammar rule
表が1回だけ出る確率は いずれも同じp 1 p 1 p で
So, of the 8 possible outcomes of the coin flips, those 3 are the ones you want to count.
3つ目は x p x p x
Valid.
P Y P Y X P X P Y X P X となります これに数字を当てはめると0 6 0 2と
You can actually compute this using total probability where P(Y) equals P(Y_BAR_X) times P(X) plus P(Y_BAR_ X) times (P X).
I said P amp P is Jane's book のような場合
But what if you want to include quoted dialogue in your string?
p 2す pを因数として切り出すと
And then when you add p squared to negative 2p squared you're left with negative p squared minus p squared.
SをPに代入したのPになります
Rule 0 and rule 1 both apply to S, so I'm going to yield 2 things.
したがってコードは 3 p 1 p 1 p になります
So, to get all 3 of them together, we just multiply these by 3.
P Y S C R I P T E R
And right here, this environment is called PyScripter.
p priority
p priority