" P の不毛"の翻訳 英語に:


  例 (レビューされていない外部ソース)

Pは初期の不確実性です
So it's 0, 0, 0, 0 please don't change it.
不毛の言葉です 私たちは
This is the language of sterility.
または充足不可能であるか つまりすべてのモデルで偽なのかを答えてください 論理式はP P P P
So what I want you to do is tell me for each of these sentences, whether it is valid, satisfiable but not valid, or unsatisfiable, in other words, false for all models.
p掛ける (p p)の1と p 2 pでp p (1 p)で 綺麗な式にまとまりました
And if you want to factor a p out of this, this is going to be equal to p times, if you take p divided p you get a 1, p square divided by p is p.
P Q P Q P Q Q P
And the sentences are P or not P, P and not P,
p 1 pで p ( 2p) 2p 2で p p 2 p 3です
And then this term over here, this whole thing over here, is going to be plus p times 1 is p. p times negative 2p is negative 2p squared.
P P
Let's say that this is our grammar
土地があまりに不毛なため
It's actually a Bronze Age culture that's been isolated.
P P とPー です
Once again, based on this P, I'm going to start bringing in rules 1 and 2.
P. T. P
F, L, E, P, T, P L, E, P, F, L, F, L, E, P, T, P, L, F, E, T.
A P P
APPLE.
P(A) Ʃ P(A B) P(B)
Now in probability terms, people often write it as follows
ご存知の通り宇宙は不毛な世界です
The galaxy's a pretty barren, desolate place when you get right down to it.
不毛, 或るものは粉々になりさえした
Barren. Some even shattered.
十年一日のごとく 不毛な仕事を続け...
You're stuck in the same deadend job. You have been for years.
こっちは不毛の星で頭がいっぱいだ
Am i?
P H R はP H R S P S
Let me just do this over here.
赤毛 赤毛
Redhead, redhead.
P P または
So chart state 0 includes the following parse states
ピンクの p を得るこの p プラス p 以上 1 プラス プラスです
Now let's add that pink p to both sides of this equation.
p 1はpです
So that cancels out.
0 pは pです
So this is going to be equal to 1 minus p.
ここを不毛の地にする必要はありません
Sterilization is not necessary.
P P とあります
Another way to think about that is let's say that we're in a particular state like this one
三毛全集 三毛
And I was inspired to study abroad after reading these.
髪の毛
I got a hair sample.
Pは P を得たあと2つ目のルールでPを消します
The first one looks pretty good. I just apply rule 1.
それぞれの値から算出できます P H S R P S R P H S R P S R
P of happiness given S and R times P of S and R, which is of course the product of those 2 because they are independent, plus P of happiness given not S R, probability of not as R plus P of H given S and not R times the probability of P of S and not R plus the last case,
P A B P B A P A P B となります P B A を尤度 ゆうど と言います
P of A given B where B is the evidence and A is the variable we care about is P of B given A times P of A over P of B.
P
P
p.
p.
P .
What's next?
P ...
P .
P ...?
P ... P ...?
P ...?
Teacup!
P
Similarly, over here I'm going to apply rule one three times.
P...
P...
ピンクの p 以上 1 プラス私はプラス 緑の p は 同じ p を取得します
Now divide both sides by 1 plus i.
P X3 X₁ P A X₁ P X3 X₁ A P A X₁ です これが全確率です
P of X3 given X1 is the sum of P of X3 given X1 and A times P of A given X1 plus the A complement, which is X3, conditional X1 and not A times P of not A given X1.
友達が死んだ 火が燃え広がるジャングルや不毛の地で
Friends like Lual who died by my side, of starvation.
脚の毛だ すね毛を剃っとる
His legs. He's shaving his legs.
あい行くぞE, F, L, E, P, T . P, L, E, P, F, L, E L, E, P, T, L, P, E, F, E, T, Z, E, T.
All right. E, F, L, E, P, T P, L, E, P, F, L, E L, E, P, T, L, P, E, F, E, T, Z, E, T...
S P P P またPが何もなしと 書き換えられるPythonコードです
It's that grammar of balanced parentheses.
3つ目は x p x p x
Valid.
p 2 p 3になります この項の値は
This is going to be, this term right over here is going to be p squared minus p to the third.