So this one is the first derivative of y with respect to x is equal to 3x squared plus 4x plus 2 over 2 times y minus 1.

Let me take the x out of that side.

So let me do that.

And we're multiplying that times two to the fifth.

If I were to say 2 to the fourth power, what does that mean?

2 times my vector v is now going to be equal to 2 times each of these terms.

So if we could say a is z and b is 2.

So we get 4x plus 1 is equal to we can factor out the 4, or the square root of 4, which is 2 is equal to the plus or minus times 2 times the square root of 2, right?

Two weeks, two weeks, two weeks, two weeks, two weeks, two weeks, two weeks...

So let's just think what two to the third times two to the fifth means.

I know this is messy.

And now we can just do it as this is the same thing as twox times twox plus two.

It seems like I see the light at the end of the tunnel.

The original problem was 3x squared minus 2xy plus 2, plus 6y squared minus x square plus 3, times y prime, is equal to 0.

If you divide both sides of this by r squared, you get x squared over r squared plus y squared over r squared is equal to 1.

And let's bring this y to this side of the equation too.

So if x is equal to 2, then what do I get?

And this is 2 times 2 times 2, thats eight

So, let's say I had the hyperbola y squared over 4 minus x squared over, I don't know, let me think of a good number.

This negative 1 and this positive 1 cancel out, so you're left with 2 roots of 2 squared, minus 8 is equal to 0.

I'm just going to treat it like 91 times 32.

Multiply both sides by b squared. y squared is equal to b squared over a squared x squared plus b squared.

The length of one is two, so all of the sides have length two.

This becomes f squared over a squared minus 1 times x squared.

And that little cube has side length 2.

And I can multiply this one out, too, you get 2y minus 2, that's just this, dy.

If you multiply the left hand side times minus b squared, the minus and the b squared go away, and you're just left with y squared is equal to minus b squared.

Let's divide both sides of this equation by a squared, and then you get x squared I'm really just trying to simplify this as much as possible over a squared minus so the a squareds cancel out minus 2xf plus a to the fourth divided a square well that's just a squared.

You add a squared to both sides, and you get f squared is equal to b squared plus a squared or a squared plus b squared.

So 2 minus 2 times x1, so minus 2 times 2.

So let's multiply both sides by 2 times y minus 1.

Two weeks, two weeks, two weeks

Actually, let me use a skinnier pen because that does look bad.

We have A, but A is 2, right?

So this is the same thing is that.

So negative b.

We just divide both sides of this equation by dx, right?

Let's try to see if we can simplify this.

So 1d.

Now, these 4's cancel out, so you're left with negative 1 plus 2 roots 2, plus 1, squared, minus 8 is equal to 0.

2 to the third power which is 2 x 2 x 2, which is 8.

Now what does this mean over here? Well, there's a couple of ways to do it. You could just say ... like, I have the same base, I'm taking the product ... so I can just add the exponents.

All that pattern matching, I made a mistake.

That is 8

I could come from here, from here, or from above.