Let me see.

This seems a little weird when we say it verbally, but if you look at it, it's more or less just what we expect.

One way to reason about this is just to write out all of the strings that this matches 0, 1, 2 all the way up to 9.

Let's see if anyone is willing to sell a sheep.

At least one resource agent has been found.

Well for every three strawberries, I have two oranges and I have one apple.

Let me draw that. So 12 groups of 1.

I'm going to start the find from the initial opening bracket and so I'll find the next closing bracket.

There's also constants, things like number one, and the number two.

Let's break it down.

Because I wrote this first one as 1 plus 5 instead of just a 6 because you could say, well look, I had a 1, and then I had one 5.

Well, we already have a 5.

If he says a thing is good, it is good.

The way the Python dictionary is implemented, there's just one flat list.

I have 2 3's.

So here's what option one would look like.

There is one problem.

The answer for B is two again, same as A.

This became 28.

Likewise, stars are crystal clear and they're bright, and so you see definitely different sizes, just like you do on Earth, of stars, that some are smaller and some are bigger.

So to go through an example, let's say we have this finite state machine.

Columns go down, rows go across.

And if you care about the remainder, it's 1.

Let's look at a very simple piece of code that implements this planning algorithm.

The abalone shell here.

Well, let me actually just draw them.

Another difference is in a kind of generic

However, what if I want to do this 2 3 first?

There is one thing I don't understand.

There's one thing I don't understand.

And if it's not the base case, we're just going to plug in the formula that we got from the problem statement.

What is it that they have been doing and where are they now? Vukosi Marivate, Graduate Student, Rutgers University

So our strategy for solving this is is going to be very similar to what you would do by hand.

Under the method summaries, there are a couple of different options for replace. Let's

Well, we have 3 pieces and each piece is 1 4, so we have 3 4 left over.

You're thinking, Well, how often am I in a hotspot?

Now we're not dealing with 5 anymore. We're dealing with 6 again.

I have this right here.

I'm going to call these actions.

And then how many new toothpicks are we going to have?

So you could view this as 1 2 plus 1 2 plus 1 2 plus 1 2 plus 1 2, which is the same thing as 1 plus 1 plus 1 plus 1 plus 1, over 2, which is equal to 5 2.

And the answer to the question is that the first four apply, but not the fifth.

Maybe I'll circle that one, I could have circled that one.

That's our procedure. Now we are going to have our paren and we are going to pass in an input.

One possible subject is students.