We're just multiplying the corresponding terms, the third term times the third term, the second term times the second term, the first term times the first term.

So how do we do it?

So the first commandment

Items one, five, seven approved full wise, stop.

So that's the area and it's a monomial.

Let me draw a vector in R3.

The first term has one 5.

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So, for logistic regression, we had two terms to our objective function.

And it controls how big a step we take when updating my parameter theta J. And this second term here is the derivative term.

It actually has 3 vanishing points

Vector Machine, just by convention we're going to use a different parameter.

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And I'm gonna sum those products. So I'm taking this term.

The scales would be tipped to the right. It's not in P. We're looking good so far.

I pick the i'th data item, and I count how often does this occur in the entire list.

OK, but I'm going to do the same thing, so to get this term right here the top left term we're going to take or the one that has row 1 column 1 we're going to take the row 1 information from here, and the column 1 information from here.

If n is equal to 3, it's going to be 5 times 3.

I'll do this right over here where I have the columns labeled with the numbers I could roll on the second die 1, 2, 3, 4, 5, or a 6.

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This is the most venerable of the happinesses, traditionally.

I'd like to share with you today.

The one green eye!

The maximum value for the first term

Set the maximum value for the first term

Set the value for the minimum term of the sequence

We have an x squared term.

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Let's divide them into groups of two.

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