You never intended to marry me!

That was after one treatment. We gave him five.

As before, without it'd be 1, but with it'd be 2 3 or approximately 0.667.

When the data is scarse, I believe faking it gives you a better result.

The correct answer is 4.

That's 500,000 a year. So my operating profit is 500,000 and that's pretty good.

What's the probability that if I do the following, I draw a coin at random with the probabilities shown, and then I flip it twice, that same coin.

I'll number the flips.

This is equal to 1 minus the probability of getting exactly one heads out of 5 flips.

It's time for some problems now,

I don't know which one I have picked. It might be fair or loaded.

Now, the way I set it up, those things here are equally likely.

And very certainly, the answer is yes.

And so this is our yield.

It's easy to see that the probability of heads in step 2 is the probability of heads in step 2 conditioned on heads in step 1 times probability of heads in 1 plus, that's the sum, probability of heads in step 2 given we had tails in step 1 times probability of tails in step 1.

Perhaps administering them,

The way I word this is by conditional probability, probability of the second coin flip coming up heads provided that or given that X1, the first coin flip, was heads, is 0.9.

So, the probability for heads will now be 0.8 and therefore the probability for tails is 0.2.

Let's say we have a sample of size 1, 2 and 10.

Give me two largebore I.V. S and start a Ringers lactate push.

Let's go! Let's go!

Parentral on the other hand, is shown over here.

It's so uninteresting.

What's the area of each of these triangles?

For a fair coin, what do you think the probability would be that if I flip it twice we would see heads exactly once?

Now let's see a slightly complicated example

It evolves.

And you'd be heavily drugged.

Ready or not,we're administering the antidote.

It's a wonderful room.

One at a time!

He went 5 innings.

But that's the easy part.

I can get heads and tails on the first as well, so the probability of heads on the first flip X Probability of getting heads on the second flip.

Turns out though, that that's not even where it stops.

This coin may have a probability of landing on heads of 0.5 and this coin might have a probability of 0.1

PrintOnce

3! Like so, to the right side.

So when will it be switched?

Make you feel better?

One guess left.

Try one more time.

One time.

So let's do one final exercise.

Can I bowl another one?