What's 3 3?

I can interpret it as two plus two plus two, or adding two to itself three times.

And the third element of this is, what, 6 5 (2 3), which is 11 (2 3), so that's 10 and one third and see, you close this square bracket.

Well this is going to be 3 3 3.

1 plus 2 plus 0, well, that's equal to 1 plus 2 is 3 plus 0 is 3, and 3 is definitely divisible by 3.

1 3 3 1 and you're left with one X so you are left with X 9 1 3, or you can do 9 divided by 3, which is equal to 3.

Which equals four thirds

Let's say I had this set of numbers.

3 divided by 3 is just 1.

And in the denominator what happens?

Each cell has exactly 6 particles in its total neighbors, so therefore, each of those cells gets a 3.

We get I'll do it in a different color we get 3 2 c1 plus 3 2 c2 is equal to what's 3 2 times 2?

So if I said, you figure out the sum of, I don't know, the powers of 3 up to 3 to the, I don't know, 3 to the tenth power.

It could also be rewritten as three two times.

And the answer is 1 1 is 2, and so that's even, so it'd be a positive payoff to E. 1 2 is 3, that's odd, so it'd be a 3.

Well, let's do that. Let's do the floor.

Divide the numerator by 3, you get 1.

So 10 3, so we might have 0, 1, 2, 3, 4.

And when we add them, a plus b, needs to be equal to 3x because we're going to split up the 3x into an ax and a bx.

So the particular solution of this differential equation I will do in a different color, and it is y to the 3 2 minus x to the 3 2 is equal to 7.

3 times 2 is 6.

So this g of 3 is equal to 6 plus f of what?

Well, 2 times 2 is 4.

And if we did that we get

And the answer is relatively easy.

I know.

Well, I have eigth equally sized cubes and I took three of the out.

I just didn't know what it was.

Did you check number three? Hi.

I can't, I have only three charges left.

If we do the same thing to numerator and denominator we're not going to be changing the value of fraction.

1...so that's 1 group of 3, 2 groups of 3, 3 groups of 3, 4 groups of 3.

We know it's 1 3 cup.

So we have three over three over four.

That whole distance is 120.

I'm going to hit count.

Well, there's 15 coins and 5 of them are fair, so it's 5 out of 15, so it's 1 3.

Row 3, column 3.

So let's divide them both by 3.

Now N refers to a value 4, but that doesn't change the value A refers to.

We can actually simplify it because 9, 3, and minus 18 are all divisible by 3.

Note that unlike Python we're indexing from 1.

Well, if I make it the product of x minus the first root and x minus the second root.

And if you wanted to write this as a mixed number, you could just say, well, 8 goes into 27 three times, and you have a remainder of 3.

So three four times.