And then if we wanted to just figure out the Laplace transform of our shifted function, the Laplace transform of our shifted delta function, this is just a special case where f of t is equal to 1.

So let's say my first parametrization, I have x of t is equal to t.

So this is going to be the integral from t equals a to t equals b, of p of p of x, really, instead of writing x, y, it's x of t, right? x as a function of t, y as a function of t.

I'm running out of space.

Give me case.

Let me do it on the side.

To prove that this is true we're going to proceed by induction.

Nacelle casings.

I want to put out a tracer on Eleanor Burnett.

I'll do it in another color, just to ease the monotony.

t

T

...T.

T888.

T750.

Let's say that that is f of t.

We just learned about this, using MDPs and value iteration.

Why are the houses in such poor condition?

I'll take the case, too.

Give me the case!

And it merges the stop sign and yield signs.

If this was just an F of s, what would f of t be?

DVB T

These two cancel out, va minus va.

You said you've got a TRex?

J.T.

J.T.?

J.T.!

J.T.!

Golf...

Tbag!

T600.

Kirk, James T.

This case also applies to other cases.

We saw, well, what if we took the Laplace transform of e to the I'll call it 1t.

We'll get dr is equal to x prime of t dt times the unit vector i plus y prime of t times the differential dt times the unit vector j.

And this is almost superficially easy.

The word two, for example, needs its W in order to mark its connection to words like twice, twelve, twenty,

Let's consider three cases.

About a day away.

Check for yourself. Open the case.

So we're going to move these dots over here and get

This is the Laplace transform of f of t.

Now we took the anti derivative.

These two are in chart 0