You have to distribute the b squared.

Take the imaginary part squared so let me write this.

We want the right side to just be x minus 1.

So the first thing we can do is we can square both sides and get rid of the radicals.

This is negative.

We want to get back to negative 3.

This isn't any kind of fancy factoring.

And if x minus 7 squared is equal to 0, take the square root of both sides.

And in the next video or the video after that, we'll solve an example where you want to take the negative square root.

Well you know, this'll work for any b, any 2a.

I cleared the roof of snow.

Or we could have skipped this step and written x minus 2 squared is equal to 9.

And that's what we want to solve for.

And now to solve here, you might want to take the square root.

So w is going to be equal to the square root of 25, the positive square root.

So if we really want to get to the x plus 2 in the appropriate domain, we want to take the positive square root.

He cleared the roof of snow.

Next, let's look at solar power.

So because this expression is negative and we want to get back to this expression, we want to get back to this x minus 1, we need to take the negative square root of both sides.

So that's a negative number.

Is equal to the determinant of your matrix squared.

I just the square root of it, and we have to get the square root of the denominator too.

When x approaches infinity, it's going to be approximately equal to the plus or minus square root of b squared over a squared x squared.

They work in the same way.

If I take negative 3 I take negative 3 and I were to square it, that is equal to 9.

So we get vf squared is equal to 2 times the force divided by the mass times the distance.

Let me show you how this works on an example.

That's just the numerator.

Oh, it's very important!

So it's x minus f squared plus the y distances. y minus 0, so that's just y, squared.

I'm sure to most of you here today.

And then, what is the radius in the x direction?

So let's see, so we get x.

They had no right to take that plant. Forget the plant.

And then to solve for a, we just take the square root of both sides, the principal square root, the positive square root of both sides of this equation.

And our goal is to get back to negative 3.

Because when this number is, like, a trillion, or a google, then this number is almost insignificant.

So we're going to be dealing with something like 3t.

These get messy. x minus 1 squared is equal to 16.

But what's interesting about this function?

We're always going to be so the positive quadrant is always going to be slightly larger than the asymptote.

Because the way our domain was constrained, this value right here is going to be negative.

But this is not about religion, it's not about proselytizing.

And minus c a is the same thing as minus 4ac over 4a squared.

So what do we do now?