Kendall's 15 months older than Jay.

These are called tau tau.

tau

tau

Tau?

And when you would put tau in there, you get tau over 2 tau, and then minus minus tau over 2 tau, and then you get tau plus tau over 2 tau, that's 2 tau over 2 tau, which is equal to 1.

Vung Tau

1 over 2 tau when t is less then tau and greater than minus tau.

So this is minus tau, and this is plus tau.

You have one tau here and then another tau there.

Ba Ria Vung Tau

The base is 2 tau.

If my new tau is going to be here, let's say my new tau is going to be there, I'm just going to pick up my new tau there, then my 1 over 2 tau, the tau is now a smaller number.

Sorry, 1 over 2 tau dt.

Things went badly at Tau Ceti.

So what is the limit as tau approaches zero of my little d sub tau function?

I mean, I could rewrite this integral as the integral from minus tau to tau and we don't care if infinity and minus infinity or positive infinity, because there's no area under any of those points of 1 over 2 tau d tau.

like the charm quark and the tau lepton.

Still leading, Sigma Tau Omega, team number 1.

You could get this is going to be equal to you take the antiderivative of 1 over 2 tau, you get I'll do this just to satiate your curiosity t over 2 tau, and you have to evaluate this from minus tau to tau.

So that everyone can do what Tau Nguyen did.

So it's equal to 2 tau times your height.

What happens as the limit as tau approaches zero?

The Sigma Tau Omega team and the Acacia team.

I heard the battle went well at Tau Ceti.

And that level, I'm saying is 1 over 2 tau.

And your height, I just said, is 1 over 2 tau.

looking at two stars, Tau Ceti and Epsilon Eridani, for about 150 hours.

So it's going to be zero everywhere, and then at minus tau, we jump to this level, and then we stay constant at that level until we get to plus tau.

So let's say that it equals 1 over 2 tau, and you'll see why

Now, if I take smaller and smaller values of tau, what's going to happen?

It was 2005, and we'd recently heard lt br gt the story of Tau Nguyen.

What Tau did was a game changer and we were so inspired by her work.

So this point right here on the dependent axis, this is 1 over 2 tau.

My 1 over 2 tau is going to have to even be higher than that.

That is, your steering angle is proportional by some factor of tau to the crosstrack error.

The Sigma Tau Omega team has regained the lead. The Cutter team has fallen into second position.

I think you're satisfied that the area under this is going to be 1, regardless of what tau was.

So when it's in the denominator, my 1 over 2 tau is going to be something like this, right?

Your Dirac delta function is a function of t, and because of this, if you ask what's the limit as tau approaches zero of the integral from minus infinity to infinity of d sub tau of t dt, well, this should still be 1, right?

By turning, inversely proportional to the y value, using a parameter tau that sets the response strength of the proportional controller.

And then over that boundary, the function is a constant, 1 over 2 tau, so we could just take this integral.

Tau, pulled out her cell phone camera, she turned the lens off of her, right back onto him and took his picture.

So then if I pick an even smaller tau than that, then my height is going to be have to be higher.

So as you take the limit as tau approaches zero and I'm being very generous with my definitions of limits and whatnot.