And so what can we factor out of that group right there?

We know that these are both divisible by 2.

Let's say that they're functions of t.

So this right here, there's no constraints.

Here is what I think we need to do here.

2 plus 2 plus 2 plus 2 is equal to 8.

Negative two ( 2) times negative seven ( 7).

Here it's minus 2 as well.

look something like that.

It actually doesn't take too long.

One, g of x.

It's a rectangle.

So we can already see the bottom of our rectangle that they're talking about, right there.

Which will be greater than 0.

So let's do something very similar to what we did in the past.

I can show you that real quick.

But we say, look, both of these things have to be true.

And that's actually the y intercept.

And the top two problems, this one right here both 1s are positive.

You could get fairly sophisticated with your mathematics.

Our torpedo and theirs.

And I'll get x is equal to 3.

Now, both of these numbers have a 2 times 2 in it, or they're both divisible by 4.

You go 1 2 3 minus 3, minus 1.

Honestly, I don't see why I can't do both

But maybe we can if we subtract 2 from both sides of this equation.

So I've written these two expressions.

We can say v1 one is equal to ac, and we could write that v2 is equal to bd.

Let's do another example.

Well, they definitely have a common factor, you have a negative 3 or positive 3 common to both of these.

Like the tragedy. Your parents must have had a sense of humor.

So let me do that last one, because I have a feeling that'll be the fastest way to do it.

You immediately see 6 and 4 are both divisible by 2, so let's divide them both by 2.

They're false for each of the first 3 and true in the fourth one, so that means that this is going to be true no matter what.

Well, let me let me just, see if i can . if I factored out

And that is also an aspect that must not be dismissed it is there, it is part of this play.

You'd have to be two.

That is their greatest common factor.

Nothing really jumps out at me.

So I could have just as easily drawn my vector like that.

You get x is equal to 5.

We could also write it as y squared is equal to x squared.

But what their asking is just to find absolutely that these both are two by one matrices.

If we subtract 18 from these data sequence, we get 11, 20, 14, 5, and 0.

One graph has a vertex that is a maximum, while the other has no, that's not right.