We're told to list in order from smallest to largest.

Deirdre is working with a function that contains the following points.

And these aren't the actual functions.

Let's just simplify this.

Run this thing itself a thousand times and each time you get a different mean, so this means zero, mean one and so on all the way to a mean nine, nine,nine.

The average of these two is 2. That's a chance node.

And then we have another 1, 2, 3 8.

Minus 4 divided by minus 1 is positive 4.

What if there's actually negative equity here?

Well, we have to look at the factors of negative 84.

What is the price for this?

Let me make the pointer smaller.

You give me any x, any y, you give any x, y in the x y plane, and these are going to end up with some numbers, right?

And so lets see is we can simplify this a little bit.

But given that definition of the mode, what is the single most common number in our original data set, in this data set right over here? Well, we only have one 4. We only have one 3.

These clipboards are filled with numbers.

And then what is my range?

This becomes because I'm subtracting negative, negative, these are all negatives.

On the open list are these three states, and we prefer the one on the right because its f value is smaller than the other two f values.

And when I say book value, that's just a fancy way of saying this is what our accountants say that we paid for the stuff.

And just the notation, z is equal to a function of x and y.

We noticed that test result also apply when the condition is not fulfilled.

Well, the way I've defined, and this one's a little bit tricky.

Well, sure.

next, check the readings from phase to ground and record these values also

And now we call greeting2.toUpperCase. After these statements, what's the value of greeting?

So once again, they're going to do a pre money valuation.

And so what 5 5?

And all you do next is divide or normalize this thing over here by the sum over here and the same on the right side.

What is minus 3?

Now here's a different hypothesis that's you know still not a great fit for the data but may be slightly better so here right that's my point that those are my parameters theta zero theta one and so my theta zero value.

So the change in y is just going to be this guy's y value, which is 9 plus 6 delta x plus delta x squared.

60 now or 50 in a month?

If the absoulte value of 2x minus 5 is equal to 11 that means that the stuff inside the absolute value sign either equals 11 or the stuff inside the absolute value sign is equal to NEGATlVE 11.

In this data, the prize is linear in the size plus or minus a constant dollar amount.

Particle b will get an importance weight of 0.2. Same for particle c.

And so the easy thing to do when you complete the square, the thing I like to do is, it's very clear we can factor out a 9 out of both of these numbers, and we can factor out a 4 out of both of those.

So a list in Python would look something like this

So I'll write that up here.

So C is equal to 6.

So we could write 7x needs to be one of these numbers.

If this was any other non negative value, you would have two values.

Let me actually draw the same scenario over again.

The mean is using the exact same formula as in the previous unit.

So let's say I had the numbers 1, 3, 5, and 20.