We're multiplying our f of t times e to the 1t.

So we could say a is equal to negative 2 same idea there and then you square it.

So you're going to get some combination of the i and j unit vectors.

And then we can essentially just add and subtract them from the center.

So, minus 2 3 x, you go down 2 for every 3 that you go out.

We'd also want to multiply the right hand side by x.

You multiply that times negative 8

Someone has to say, well, when x is 2, y is 3.

You take a vector, you dot it with itself, and you get the

This left hand side, negative 12 minus 8, that's negative 20.

So let's multiply it by 2.

And then we distribute again.

And now I evaluate this at 1 and 0.

let's just divide by a again.

So this was c plud d i, so this is its conjugate.

We multiply the denominators 3 times 2 is 6.

So you get this 5 right over here.

And so, if we just put this on the other side of the equation, what do we get?

Transform of any arbitrary function very, very quickly.

This is Brad doing one of the Ekman FACS poses.

We have AC and DC, get 12 volts DC, so that could be used for certain applications.

3 minus nothing is 3.

Is greater than 3 minus 7 which is negative 4.

And if we factor out a 5, what do we get?

That's what multiplying times 10 to the negative 8 did for us.

4 and negative 21 look tantalizing, but when you add them, you get negative 17.

If you distribute this negative sign, you get negative b plus a, which is exactly what this is over here.

And if you'd give me some other point right here, I'll relate it to another member of y.

Time, publications, and gender.

If you distribute the negative 3, you're going to get that expression.

Got it.

Is, it's a conditional probability.

Well we're asking ourselves or this will evaluate to the exponent that I have to raise 8 to, to get to 2.

Now what it means is 52 times the result of adding 3 12, which is 15, times 9.

Look, they got matching bracelets.

You may get it free of charge.

When I multiply this thing times my little delta function there, I get this.

And we can verify. Let's try all of the different scenarios again.

In 3 cases, A is followed by A over here, over here, and over here.

This 10 times 5 which is 50 and you would have gotten the same result.

Let's factor out the x plus 7.

If you divide negative 16 by 8, you get negative 2, times 3 is a negative 6.

5 times 9 is 45.

Now if I multiply this whole thing times dy,

The next time through the loop, i is now going to be 2.