The next time through the loop, i is now going to be 2.

I can just multiply both sides by dx.

And then one times zero is zero. one times four is four.

And then you give a negative 2, this function will pop out a 1.

I'm going to run out of space.

If we just 1 2 of that, if we just want the radius, we just multiply it times 1 2.

How many possible rolls could we get?

And your ratio is twenty forty, which is two four, which is the same thing is one two.

So we're in this scenario right over here.

So if we multiply both sides of this equation by 2 b minus k, you get 1 is equal to 2 times b minus k.

And then, that was that one, then there's the middle one, and now we get the row 1, column 3.

So you cross out that row, that column.

The a's cancel out.

We already figured that out.

But anyway, let's go back to this position 1, 1.

Or you could also view it as 0.992.

So you're going to get some combination of the i and j unit vectors.

So if you borrow 1 at 100 interest, if you borrow a dollar, in a year from now, I want that dollar back, and

So here, they're saying,

Let's divide both sides of this equation by 20.

To start off with, we haven't got any information, and we look at 7 well, that's my current one, and there's one of them.

So, minus 2 3 x, you go down 2 for every 3 that you go out.

We'd also want to multiply the right hand side by x.

You multiply that times negative 8

Someone has to say, well, when x is 2, y is 3.

We won't know necessarily which of these regions are actually an object and which of these are not object.

Let's pick f of 5. f of 5 is equal to negative 1.

Let me clean this up so we have some space to work with.

So there is a 1 minus p probability that we get failure, that we get 0.

And so, if we just put this on the other side of the equation, what do we get?

3 times minus 1, plus 1 times 0, plus 2 times 2.

And I think we get the same answer.

So the first item here will be included, the last item here will not be included.

Then when we get row 2, column 2, we cross those two out, and we take the matrix of the minor that's left.

The ratios become idiotic by the time you get to ethanol.

And then we distribute again.

And now I evaluate this at 1 and 0.

let's just divide by a again.

So this was c plud d i, so this is its conjugate.

We multiply the denominators 3 times 2 is 6.

When I just algebraically manipulated this equation, I got 1 plus y over x.

We could put it over here and you would get straight to 2 1 6.

You divide the numerator by 4, you get 9.

3 minus nothing is 3.

Transform of any arbitrary function very, very quickly.