All this other stuff gets factored out.

At each meeting, there's way too many ideas.

I trust my 1 .

We must continue on this route for 23.8 miles.

A student who received the highest GPA in both, a 4 and a 4, would be right about here.

Well it is just going to be seven.

Sorry, sorry.

I plan to work the rest of the summer.

I'm staying.

Once I'm finished taping, then I put it in my computer, and then I'll scan it and take a peek at it.

Well just on this simple diagram we have 8 million

E can be rewritten by INT. E can be rewritten by INT.

I'm going to start with the first element of my list and make it the root or the top of the tree.

This times this.

OK, now I'm going to change gears here.

So, it's logical that you'd have one there, on the minor road entering the major.

We see 2 goes into 13 six times, 6 times 2 is 12, you subtract that from that, you get a remainder of 1.

And that and that cancel out, and the negatives cancel out.

Seeing the other landmark from x1 and x2 means we fill these guys over here.

So a good place to start is maybe to just isolate the absolute value of y on the left hand side of this inequality.

We can subtract 49 from both sides of this equation.

So we're subtracting 3 from that side, and subtracting 3 from the right side.

The right hand side, I got rid of that 6y.

And we are left with

Now if you divide this term by 3y, all you're

If I had 3 of something, and I take away 1 of them, if I take away 1 of them, I'm left with 2 of that something.

We can't just erase them, but we can forward them back into the surviving matrix by the following simple operation we take the surviving matrix to be called omega prime and the surviving vector to be called X prime, and you can get omega prime and X prime by using the function take that is in your own matrix library.

Do try to activate what's left of your memory.

Yeah. sir?

There's some leftover food in the fridge.

We have 2 times 1 2, that cancels out.

We subtract the green expression from the light blue expression and we're left with this.

Only the x most recent messages are kept on the server

And we're left with a times 3a minus 5, over 2 times 2a plus 1.

So what are we left with?

There's just one last enemy to deal with.

The total of those is 1. The quarter is claimed by heads.

Well, this x plus two and this x plus two will cancel out.

Down here we can factor out a 2x let me make it in that same color. We can factor out a 2x plus 5.

This is 1 million, this is 750,000.

We now let these particles survive somewhat at random, but the probability of survival will be proportional to their weights.

Now, by giving this information to the rest of the group, by screaming green or purple.

Pieces of rusty nails

When you multiply by one third, visually, over here, if you had 3 X's and you multiplied by 1 3, you would have only one X left.

And then something very dramatic happened.