So chart 1 had a dot in front of a big (Q).

But instead of its vertex, or its center or its starting point, or whatever you want to call it, to be at the origin, it's shifted now.

Let's say, minus 5.

I suspect he was late for his duty shift.

And then I'll do another video where I actually shift the hyperbola.

Well, then this will just shift this Laplace transform by 1.

So when you take something to the negative times 10 to the negative power, you shift the decimal to the left.

It's scaled up.

Then the right scan line we get to see the following.

Notice it did exactly what I said. x minus 4 squared was shifted four to the right. x plus 2 squared, was shifted two to the left.

You do x squared plus 1.

I didn't give price why don't I just hold off a little bit and wait a little bit so it's going to lower demand so in this scenario the whole curve will shift to the left at any given price point the quantity demanded will go down at any point of that curve, so the entire demand curve will be shifted to the left, so because of senario two demand was decreased.

And we established this was our f of t, so we just shifted it by c.

And so essentially, it will shift, it will change the entire demand curve.

And then let's have the square root of x plus 4.

It might be a little non intuitive that you say minus 4 to shift to the right and plus 2 to shift to the left.

We go over both of these fields or any number of fields that exists over here.

I have an e here.

Shift

Shift

(Typing noise) (Typing noise)

And remember, these are the asymptotes for this situation.

But the way to recognize that is that you have this minus of the y squared term and then we actually have it shifted.

And that's a bit magical for now, but we'll see why we want to do it, real shortly.

This is the Laplace transform of e to the and what's a? a is what we shifted by.

I'm working on this hyperbola right here, not this one, and then I'm going to just shift it later.

Laplace transform of, and this one here?

Now we're going to look at the input again and see that the next token is actually (q).

Those are the as but this one's centered at the origin, because it hasn't been shifted, and then that's those two lines right there.

If I am not mistaken, this is Mr. Robert Rainsford... who hunts big game so adventurously.

But what if (C) is a terminal a token, final part of the input?

Well, let's just do this the fast way.

Shift left

Shift up

Shift down

Shift right

Hatcher's got you working a double shift?

SHIFT and Enter! SHIFT and Enter!

Dirac delta function.

In the case of exact motion, we have a perfect robot.

Here, the next input token is a (b).

Then the Laplace transform of e to the 2t times t the third is going to be this shifted.

left, and you would have to add another 0.

But let's say e to the yeah I'll just write it e to the 1t times cosine of t?

So this point is equivalent to that point.