Let's take a look at that. Let's think about adding some edges here.

Edge Smoothing

Find Edges

Detect Edges

Edge Detection

Okay, on each of the edges of the graph.

Top Edge Detection

Right Edge Detection

Bottom Edge Detection

Left Edge Detection

So given all these nicely decorated nodes, we now have a rule for figuring out which ones are the bridge edges and this is the rule.

The approximate diameter, it's a three inch (3 ) shell mill

It looks like b was our winner.

But with a Warren Ellis edge.

You have a Warren Ellis edge.

Now, the BA edge is already in there, but the BC edge is not.

So, this is the vertical mask applied to finding horizontal edges.

Create a New Edge

A graph with one node has no edges.

I'll just hold on to it for a while.

Here's a planar graph on five nodes.

Now what would happen to the H value or the L value if we had one of these edges.

There are two different ways that we can add to this graph.

In that case, the formula still holds.

'Havel 1936' starts with an uppercase H.

In the case where the success probability is 1, every possible edge will be created.

I think you like living life on the edge.

But that orientation distribution corresponds to edges in the image.

That property is kind of obvious, perhaps, but we were almost there.

Select the rectangle tool again and start from this upper edge.

There are n 1 other nodes if you choose one center, and each is connected to the center node with one edge so there are two n 1 edges and that seems good.

For each of the edges in the graph, we have three of these statements to rule out all possible color matches, so there's three of these for one edge, two edge, three edge there's four edges in the graph so we have four blocks of these.

We need red bigger than the difference, no.

Here we have four nodes. That's a power of 2 2Â .

So, what we're going to do is we're going to take this entire graph and express it essentially as a tree, but some of the edges aren't going to be part of the tree.

The correct answer is Marcie.

So we can answer this question in constant time if the number of edges is greater than 0, no.

Alright, well that's it. Those are all the edges.

It'd be nice to be able to answer this question in a little bit more generality.

This is still not quite what we're looking for, but let's do an analysis of this graph then call it a day.

And let's look at how the difficulty of the question differs as we change K. So K is 1.

If you think about three times the number of regions, the number of edges has to be at least that big, though, we're counting each edge twice, because each edge can actually participate in two regions.

You can now just focus on that graph. So here's our graph.

Well, the same basic idea as we used last time applies.

Well, for the states 1, 2, 3, presumably, I could just pass in a list of the states.