Kill them.

You can just keep going below 40.

Now, to solve for x, you might be tempted to just take the square root of both sides here.

The first way is, I think, on some level, the simpler way.

What are both those things about?

So, what can we do now?

The end result would be the tuition is 200, and the number of students enrolled in 150.

Start with one square and draw another next to it that is the same height.

Rational is not a subset of irrational, they are exclusive.

Also you could take use INT the INT function which will convert that string into an integer.

This is the exact sum, just in the reverse order.

She can speak both English and German.

So in this situation there is no overlap.

Or x minus 6 is equal to 0.

So going back to how we did these problems before.

Our torpedo and theirs.

Let me put that in both places.

We're doing this case right here.

Let's multiply let me scroll to the left a little bit

And I would get x is equal to negative 7.

Sal Let's check our answer.

And the best way I can think of doing that is just to add 20 to both sides of this equation.

We have x squared on both sides of this, we subtract x squared from both sides of the equation.

Let's do another example.

Sugar, lemon, or both? Both. Mrs. Mulwray, I don't want to drop it.

I'm sorry to keep you both waiting.

And now we could square both sides of this equation right here.

You have time to (Laughter) you have time to alert one house.

When you listen to stereo on your home system, your both ears hear both speakers.

They put all the x's and the y's on the same side, and we can do that.

And the top two problems, this one right here both 1s are positive.

So this is our other solution.

You get x could be equal to 8.

And I substitut it for n.

Maybe Ben earned 50 and Abby earned 0.

We'll, they're both non invasive.

When x is 0 here, 0 plus 3 is equal to 3.

I get 2v over 1 plus v squared dv is equal to 1 over x dx.

So two is greater than one.

In each new element of a list that was encountered, figure out where it would fit into that top two lists.

We could just cancel these 3's out, or you could imagine this is the same thing as dividing both the numerator and the denominator by 3, or multiplying both the numerator and the denominator by 1 3.

And there's nothing I can multiply two by to get three.

And if we just look at this by inspection we see, well, they both share one, but that's nothing special.

Well, you look at it here, it's going to be this point.

So one way to solve these systems of equations is to graph both lines, both equations, and then look at their intersection.