You know, we're supposed to start with the A's. Then we go to the B's.

Let's go see if we can make a more natural feeling regular expression that actually does it though.

So here I have a finite state machine representation of that regular expression.

Now let's say we've seen one part of the input.

It will help to actually have names for the other nodes, so I'm going to add these in.

A and B gun tracking and firing. Multiple targets.

And then if I were to add a plus b, I go to the starting point of a, and then the end point of b.

It's in the string but it doesn't match this regular expression, because it starts with an a and none of our things start with an a.

A chord of

I'll collect all the questions from the world and answer them

So this is equal to s a times the Laplace transform of sine of a t.

Let me just show you what I mean by that.

To remind you, we covered A star and dynamic programming in class.

And they tell us that the ratio then the ratio of apples to oranges becomes one to four.

(Laughter)

And what do we get?

The top point B and the bottom C

That doesn't change throughout the whole problem. So we're starting off with a apples and o oranges.

This put your finger on the state method is actually pretty much how you do it.

Alright. We noticed that all of these strings start with a lowercase a and S starts with capital A.

And I want to welcome you all to Phoenix Club's first party of the fall semester!

So let's divide by a again, so one over a.

Ray AB starts at A or has a vertex at A and lets say that there is also a ray AC.

Now, this takes a little bit of reasoning.

And, we'll also have problems with entity names, like the movie, A Bug's

I just have to add the exponents cause I have the same base and I'm taking the product, that's going to be a to the eighth power, and I still have this three out front.

It's x minus the x coordinate of the focus.

And what do I mean by perfect square?

The beginning?

Or the other way, you could imagine, is when you decrease the exponent, what are we doing?

left with an a in the numerator, and a divided by a is just 1.

O point five gets rounded down to zero.

Let's call our function gcd. It takes 2 inputst that are integers a and b.

This is a state that will occur in our chart, but it occurs in chart state 0.

So that means that f of x has to be less than positive a or greater than negative a.

So to go from a to the minus one to a to the minus two,

We have 3 different if statements.

Well, this is equal to a times a to the zero.

180 plus 36 is 216.

Because that's the coefficient on the x squared term.

Plus this a times that a.

So the intuition is that this is going to be 2x times you know, plus something.

That's a start.

A way in.

So this term now if we substitute r3 with that, this will just turn into a this will just turn into a plus 1.