Let me do a final quiz. This is related to playing golf.

So therefore the answer to this question would be 0.5, or half.

Let's substitute this into our original equation.

And the answer is 3.

So we'll have A times the second derivative of this thing.

All right, next we have a bit of a trick question I'm importing the regular expression library and then I'm calling re.findall on the regular expression a z

Not just is a ball in a cup.

We will observe that P of A given X1, X2 and not X3, the expression on the left can be resolved by Bayes' rule into this expression over here.

Now, what happens to be true is if we take the average x and the average y, then this equation is still correct.

Comes and goes, the pull of the tides

And I think it's good moral exercise.

Rule 4 goes to b, giving me ab.

What I've done here is what's called a derivation.

We put an ad in the L.A. Times.

A over that I can now just verify that A times A inverse the identity is, type A times the inverse of A and the result of that is this matrix and this is one one on the diagonal and essentially ten to the minus seventeen, ten to the minus sixteen, so Up to numerical precision, up to a little bit of round off error that my computer had in finding optimal matrices and these numbers off the diagonals are essentially zero so A times the inverse is essentially the identity matrix.

And, the software lets me compute the inverse of A very easily.

This file does not seem to be a valid keymap. It may be a keymap using a legacy format. The import ca n't be undone!

Four years ago I worked with a few people at the Brookings Institute, and I arrived at a conclusion.

Well, phi is equal to A over B, which is equal to A plus B over A we know that A plus B over A is the same thing as

Exposure Time

It's a function of 2 variables A and B.

It takes 2 parameters to specify P of B given A and P given not A, from which we can derive P not B given A and P of not B given not A.

What is the probability that this particle, 'A', is sampled at least once?

And it turns out that we can measure that very precisely.

Navy then scrambles two F18 for escort.

Same for P of B.

So, the sum A comma 2 and this sums up each row of A and each row of A also sums up to 369.

It's been a gas, been a flip, been a hell of a trip,

It's one of the strings that I can derive.

Poor planning on my part.

Expectation maximization is a probabilistic generalization of k means.

It has no preference whatsoever. That is really the result of moving many, many times.

The beginning and ending nodes are different though.

In the case where it's odd, it's a little bit more complicated. Pull one of the b's at.

I could write epsilon. This means more_digits goes to nothing.

A single click on a file will select and focus, a double click opens the file or steps into the directory.

Let's distribute all of these constants.

Code Alpha alpha delta.

I said in previous videos that you can derive the quadratic formula by completing the square.

Here I've written out a grammar.

These variables are conditionally independent.

So, what does that mean?

So this'll be a because I just distribute the a, right? a times a to the zero, plus a times a to the 1, plus a times a squared, plus all the way a times a to the n minus one, plus a times a to the n.

And then, I'm gonna use a and b to denote the results of the two recursive calls, okay?

In the graph, we can talk about something called an Eulerian path.