We want the right side to just be x minus 1.

This isn't any kind of fancy factoring.

And then, let's see, I want to get rid of this minus, and I want to get rid of this b squared.

And if x minus 7 squared is equal to 0, take the square root of both sides.

And that's what we want to solve for.

Distributive property.

So what do we do now?

So w is going to be equal to the square root of 25, the positive square root.

So let's see, so we get x.

So because this expression is negative and we want to get back to this expression, we want to get back to this x minus 1, we need to take the negative square root of both sides.

They know, they learned, they will make better decisions.

You get p is equal to I times 1 plus i.

My parents are both dead.

Both of my parents are dead.

Both of my parents have passed away.

Minus that pink p times 1 plus i.

large, we can then simplify that get rid of all the, both the angular terms and just have the radial term.

We have 3x is equal to 225.

So what can we do?

So we get vf squared is equal to 2 times the force divided by the mass times the distance.

So it's equal to 3x squared y plus xy squared.

These get messy. x minus 1 squared is equal to 16.

We could also write it as y squared is equal to x squared.

Im going to do both right now.

You have to distribute the b squared.

Now, to solve for x, you might be tempted to just take the square root of both sides here.

So in the top, in the numerator let me switch colors both terms are divisible by 4 and a squared.

Our generation has seen both approaches tried, and often fail.

Now, what if I were to ask you, is there an x and y pair that satisfies both of these equations?

And then to solve for a, we just take the square root of both sides, the principal square root, the positive square root of both sides of this equation.

I contacted my parents.

You can divide the numerator and the denominator by 9.

And interesting enough, both of these terms are on this side.

Or you could say if x is great well, you could go both ways in that.

And minus c a is the same thing as minus 4ac over 4a squared.

Let's see what happens to our subsitution.

I really had a hard time.

Take the imaginary part squared so let me write this.

I mean that's its primary objective, both its program and its architectural conceit.

I am going to import a reference from ERlC as an example, but this method can be used with many other databases.

like this, you have to make them have the same denominator.

So that would be 3x squared plus 1.

So one way to solve these systems of equations is to graph both lines, both equations, and then look at their intersection.

I'm not going to take nothing out of the bag I assume.

Now if we want to put our x's on the lefthand side, we can subtract 3x from both sides.