All right, let me see if I have to copy and paste this one.

You people oneone?

I could also have written this matrix and 0, 2, 5, 3, 1, right.

To test auto merge, copy a line as used in your files.

1, 2, 3, and so on.

Now, inside the cost function. It turns out each of these terms here is equal to zero.

I meant less than three, third and fourth elements are less than three.

OK, but I'm going to do the same thing, so to get this term right here the top left term we're going to take or the one that has row 1 column 1 we're going to take the row 1 information from here, and the column 1 information from here.

And what are three ones?

To see this, we know that the probability of tails is 0.

Oh, we were expecting a left parenthesis. Great. I just move my finger over to the right.

V by one, this is ones of three by one.

And finally for the last one I have two one times one five, so two by one, plus one by 5, which is equal to a 7, and so I get a 7 over there.

Let's plot those 2.

Maybe in a week, a month. Maybe never.

This is 1 8.

He's from a...

So the first expression is 0 and the second one is going to be 0 as well.

So that is one section right over there

So it's 0 times 1, minus 1 times 1.

With n characters, how many ways of segmenting could there be?

We're going to take one 1 from the 9, so let's do that.

After my first measurement update,

If you divide that by a thousand, a picometer, so a picometer is one thousand billionth of a meter, or you could say a trillionth of a meter.

So 1.2 10 to the fifth is 100,000.

So one third is going to sit right over there.

And it makes sense, right?

So, for example, the inverse of two is a half, and the product of two and a half is one.

Let's see, it'll print... 1 through 9.

How many ways to get here?

I'm going to make a new list down here that's the output of map, and we're going to take 1 and square it, so we get 1 x 1 is 1.

5 8 is 13. And so on.

Well, it's the same thing.

So what you need to do is rewrite 9 8, and you know that 9 8 is the same thing as 1 and 1 8, right?

The Bag of Words representation is the following.

Well I get 1! This right here is 1

And you use the same logic each to these.

You're on the positive side, from zero to positive one, on the negative, from zero to negative one.

We're just standardizing, the variances to be one.

When you go to negative 1, we get smaller and smaller.

This is 4, 1 4ths, another 4,1 4ths another 4,1 4ths this is another 4, 1 4ths.

And we add all these up.

What numbers do I have left?

The last one is analogous.

Is it zero, one?