We again have an open list, and we add our state, we write down the g value, but we also write down the g value plus the heuristic value.

This was 0 over here, and it's 1 for these 2 states in red.

It was eight in both cases.

That's all there is to implementing A star.

H is the same idea except of those that same set that we computed for L, we want to know the largest value. For G between

So the sum of the two is 9, and I call this the f value.

F and G the largest value is three. For E between E,

You can see these different elements being taken.

Then the next line of code I compute the new sum of the g value and the h value.

I want to use the cost function of 1, so each step costs you exactly 1 for now.

G of Z approaches infinity, G of Z approaches 1, and so because G of

The one up here is called 3 2, the one on the right is called 4 3.

We get to this one over here, the g value increases to 6.

This term g prime of z3, that formally is actually the derivative of the activation function g evaluated at the input values given by z3.

That here gets me the element with the smallest g value.

For that it's important that the g value comes first in each of the triplets.

So with the heuristic function I've given you of simply the minimum number of steps it takes to get to the goal in the absence of obstacles, you can now construct an algorithm that implements a star by maintaining not just the G values but also the F values, which is G plus the heuristic.

We always expand the one with the smallest g value, but these are equivalent.

g

g

G

Assistant director ... G.Chikina Assistant cameraman ... M.Popova

G...

G.

Expand this one into a new successor. the only one that's not checked yet in the table is 1, 1 , which gets a g value of 2.

That's very straight forward. I call it the h2.

It has a preference to expand this node over here over the node over here.

The first guy's coordinate are 3 3. The second guy is 4 4.

It's also not very efficient, but it does the job for now.

For n 4, we have two n 2, right?

Art directors S.Alimov, G.Arkad'ev

Golf...

The answer is that we select this path first the one from Arad to Sibiu because it has the smallest value 393 of the sum f g h.

So now we have five tubelets where g is defined as before.

Everywhere where we saw an x, we replace it with g of x.

Because so it would be 2 times g of x.

G. JACK Clock

Michael G. Hansen

Alberto G. Hierro

ORGANEZIEZD.

F.A.G. over here says that we got too much ammunition.

G?

Let's now expand this node.

I also included h over here. That isn't necessary, but I did it anyhow.

That's why I put it first, right before the x and the y.