I subtracted 3X from here

What is 6 subtracted from 10?

I just subtracted 1 from both sides

We subtracted.

What if we subtracted 1 from both sides

I just subtracted eighty five from the current age.

Well. I remove the Y from both sides. So I subtracted Y from the left hand side and I subtracted Y from the right hand side.

I just subtracted 750 from both sides of this equation.

I just subtracted 16 from both sides to get here.

We subtracted 6 again.

We subtracted 6 again.

And then I subtracted 84 from both sides to get this.

Well, I subtracted this from here, on the left hand side.

I just subtracted the three, I subtracted the two from the three to get one and I kept the denominator the same.

Then to go from 9 to 3, well, we subtracted 6 again.

So I subtracted 20 from the left, let me also subtract 20 from the right.

We subtracted 5, x minus 5.

Oh no, we subtracted 2b from that, so minus b looks like this.

I just subtracted Chelsea's velocity times time from both sides of the equation.

And then to go from 3 to negative 3, well, we subtracted 6 again.

I added 1 and I subtracted 1.

I'm saying if theta gets, you know, this vector, alpha times delta subtracted from it.

We subtracted it, so let me clear it.

So we went down by 6, we subtracted 6.

The third term is going to be 12 from the first term, or negative 6 subtracted twice.

So we took the x and the y, we subtracted that from both sides of the equation.

Here we see Hubble diagrams with the main trend line subtracted a particular model subtracted and then residuals fit for variety fodder models.

Now I add the zeros, just because this zero and this five need to be subtracted from something.

All I did is I subtracted 100 from both sides of this equation and I swapped the sides.

From the camera's point of view, if we subtracted 5 from all the world coordinates, everything would be nicely oriented for the camera.

First, he subtracted c from both sides and he got ax squared plus bx is equal to minus c.

What the rest of the number is after I've subtracted 128 from it if it was 1 or nothing.

And then I subtracted 3, which also shifted it down 3.

We could have subtracted 5 from both sides and gotten x squared minus 4x minus 5 is equal to 0.

We could have had this plus c1 here, then subtracted both sides.

It's beautiful to see that the value function is effective the distance to the positive absorbing state times 3 subtracted from 100.

And all I did is, I took the focal length and I subtracted

You could have subtracted 1 from both sides and you would have gotten x squared plus 18x, plus 80 is equal to 0.

We just subtracted negative 6 once, or you could say, minus 1 times 6.

If you start at 3 and you subtracted 2 you would end up at 1

And the whole reason why we subtracted 5 is because we wanted this 5 to go away.

If I had subtracted 6y from both sides I would have got a negative 13 on the left hand side, which would have been a legitimate thing to do.

Very simple. Two matrices can be added or subtracted, if, they are of the same size or same order.

So even though they were trying to get rid of this 2x and they should have subtracted 2x from both sides they inadvertently added 2x here so they said 2x 3x 5x.

So if you take the number of texts J.T. sent, subtracted 25, you'd get the number of texts by his older sister.