Value in X

That's his x value.

Absolute value of 10. or the absolute value of x, when x 10.

The absolute value of x, when x 12.

If you take any x value let's say you take a positive x value.

To figure that out, you could say, look at any x value here pick any x value I have exactly one f of x value.

Find the absolute value of x when x 5, x 10 and x 12

X X X is going to be my key and X is my value.

And then what's this x value?

It has the same x value.

This is the larger x value.

So whatever x value I have here, this is also the x value of the focus point.

Put differently no what matter value X assumes, whether it's X or not X,

Let's call it the value of x.

What x value makes that equal 0?

Let's say, x has the value 37.

The one x value that would make this undefined is the x value that would make the denominator equal 0 the x value that would make that equal 0.

So, let's just think about absolute value of x, when x 5.

If I increase x value by 2, what's happening to my y value?

And here, what x value makes this 0?

What x value makes this whole terms 0?

They both have an x value of 3.

In this choice, the value of x changes.

So you can't have two f of x values for one x value.

This can take on some value, depending on what the value of x is.

And they say, what is the value of x?

And then I print out the value of x.

Well, what's the value of x here? It's 1.

Well, we could put any value in for x.

That's the natural log, the absolute value of x.

Where the curve is at that value of x.

Because remember, the slope changes at every x value.

So, right over here, this is our value of f(x) then as we get closer, this is our value of f(x), as we get even closer, this is our value of f(x).

For that x, this relation seems to have two possible f of x's. f of x could be that value or f of x could be that value.

But the vertex are the coordinates given by this x value and this y value.

But then for negative values, the absolute value of x is equal to negative x.

Let's say x is a real value random variable, so x is a real number.

I'm picking maybe v for x value of the vertex.

So its x value is going to be negative 4.

And lastly, we set x to the value of a.

Which value of x serves as a counterexample to prove

You're defining two possible y values for 1 x value.

Which of the following could be the value of x?

So the smallest value x can take on is 1.

When you put x, y here, you're going to get some value, when you put x, y here, you're going to get some value.