If you add them up, they are actually 0. So we have to add up something else.

I meant less than three, third and fourth elements are less than three.

Well, what does summation say is that this term over here.

We said what if we took a third of these things?

And I just came up with some random numbers.

So if you cross out the row and the column, it's this determinant.

This might be a coin where heads is on both sides.

We're going to insure that every number appears once in every column, and once in every row.

So the general solution of this differential equation is y is equal to c1 times e let's use our first r e to the 3 2 x, plus c2 times e to the 1 2 x.

Ah, the majority. That makes me feel very good as a doctor.

These particles together comprise our estimation after the motion command over here.

Call!

So the ratio of apples to oranges to strawberries is one two three.

3 times minus 1, plus 1 times 0, plus 2 times 2.

OK, but I'm going to do the same thing, so to get this term right here the top left term we're going to take or the one that has row 1 column 1 we're going to take the row 1 information from here, and the column 1 information from here.

But anyway, let's go back to this position 1, 1.

So I could have the matrix 1.

There is one each time.

That's not too hard.

If I were to draw it on a number line right here, that is 0, that is 2 and 1 2, and that is negative 2 and 1 2.

So that's two.

And I will explore all of them.

And then I have a fourth half here.

This right here represents 5 tenths.

So what is it going to be?

I had 3, I had thirds.

And just to verify this, imagine distributing this negative sign, or if this was a negative 1.

It's a little messy.

To see this, we know that the probability of tails is 0.

But if you cross this row and this column out, you're just

What numbers do I have left?

There's n possibilities there.

So this will become one whole and 1 2 left over.

Same thing true for negative 7 and 1 2, the absolute value, it's exactly 7 and 1 2 away.

Or I could say, here are all the scenarios where I roll a 1 on the second die.

So this is syntax for I equals one colon 10 that makes I loop through the values one through 10.

We are moving along the curve.

6 36 they are both divisible by 6 so you can divide the numerator and denominator by 6.

There is no contradiction here.

Well, we've moved 1 of the 4 spaces towards 1.

If you end up having a different feature that winds being between 2 and 0.5, again, this is close enough to minus one and plus one that, you know, that's fine, and that's fine.

So there are lots of different ways we could define bigger.

We're going to take one 1 from the 9, so let's do that.

If you look at the picture over here, you'll find there are many different linear separators.

If you were to take each of those micrometers and divide them into a thousand sections, you would get a nanometer, so now we're one billionth of a meter.