A guidance counselor.

Guidance counselor?

I have to see Hyland before he leaves.

We see the a, self loop back to state 2. We see the 1. We're in state 3.

Hyland said it was okay.

Data to Counselor Troi.

I got just the person for you,ray.

You talk to the sleep therapist yet,buddy?

School counselor told you this?

If I'm in 4, fall off the world.

In state 1 on a 'q', you loop back to state 1.

You need help? You want a counselor?

Gee,don't ever look for work as a counselor.

Since 3 is an accepting state up there, 2 or 3 is an accepting state down here.

If you quickly look at it and think about what's going on, once you take a path down the b to state 2, you can never get to the accepting state.

Don't psychoanalyse me.

You know Mr. Hyland, right? Your teachers' union rep.

Here if I was in 2, 4, 5, or 6 and I see a c,

And on b we go to state 3, and then from state 2 on c we go to 4, and state 3 on d we go to 5, and 5 on e goes back to 2, and 5 on f goes to state 6, and 5 on g goes all the way back here to 1, and our only accepting state is 6.

Well, he was the head counselor at the boys' camp, and I was the head counselor at the girls' camp.

From state 1 on b, we go to state 2 as well a or b.

I haven't left the house in a week.

All right, well, what if I see a b?

4 and I see a b I die.

How about 'aa'?

Well, one of our edges is at state 1 on 'a.' State 1 on input 'a' goes to state 2.

That's our self loop.

Finally, let's consider the string '2x'.

Dave needs a little help from the love doctor.

I wonder what a shrink would say if he saw them.

Next thing you know, we got a guidance counselor at our door.

But let's just finish checking up on c just in case we missed something.

Over here, I have defined edges, just as we suggested.

Well, one possibility is that we're already at the end of the input, at which point we should just check to see if our current state is an accepting state or not.

Guys, guys! Who do I look like, Maury Povich? I'm not your marriage counselor.

I couldn't explain why she would tell

Well, when we enter the non deterministic machine, we could only be in state 1, but after that we could see an a, and if I see an a I could be in 2, 4, or I could take the free epsilon transition to 5, or I could keep going and take the free epsilon transition to 6.

In my converted world, the state accepts if any of its corresponding original states also accept.

6 and I see a b I die.

I haven't made any progress, so I'm going to stop following edges from the 1 along that path.

This new finite state machine will still accept 1, 2, 3.

Well, sure.

I'm transferring you to another counselor.

John Why would I spill my guts to my foster dad or to a guidance counselor?

Now, there's some other ways to get out of 2, 4, 5, and 6, and when we do, we might be in states 2 or 3.