So this thirty see right there, this is three zero so I'm going to borrow one from it and it becomes twenty nine.

Let's go run it and see.

Sal, that looks like a little bit of magic.

You take the real part, which is 5.

Thanks for coming after me. Now I owe you one.

So you go 3 to the right.

1 over 3 squared, and then we have 3 to the 0 power, which is just equal to 1.

Subtract.

So let's bring another 0, lets bring another

What are you doing in here?

We don't have enough up here, so let's take 1 from the one's place.

3 times 3 is 9.

The Filofax view prints one week per page, so all days have a large surface.

And this zero will then become a ten, right?

This is just a 4 right here.

Here's the number that actually intersects with one of the ones that your investors are worrying about all the time.

Let's bring down another 0.

I actually do know one that's pretty good.

Well, we know from traditional borrowing that we have to borrow 1 from someplace and make this it into a 15.

I just went to a school and she has been absent for a week.

110 minus 100 is 10.

What happens at the depth here?

If we're going to borrow 1, I'd say, well, can I borrow the 1 from the 0?

I haven't seen christina in a week.

That's not pretty either, but it's true.

5 minus 4 is 1, 1 minus 1 is zero.

So, turns out taking this matrix and dividing it by four, this is actually the same as taking the number one quarter, and multiplying it by this matrix.

Whereas, an MDP solver can only do that once it knows exactly where the rewards are.

You have successfully completed Homework 1 Part 1 .

Now, node 6 is connected to node 2, so we'll draw that connection.

So late on the first day!

You get a 10.

Now we can at least bring out the decimals place.

So, to get all 3 of them together, we just multiply these by 3.

Setting up breakpoints trying to figure out what's going on and no time asked.

Then, the current element is 5 whoa! Happy day in jubilation.

Columns go down, rows go across.

We're looking for parse token c, and the current token is exactly c.

Sometimes being creative about how you valuate things is actually really useful.

The harder question is How often will an object come out of the pipeline being fed with objects?

Well this entire time, what is it getting closer and closer to?

So you go 1, 2, 3.

So we cross out row 2, column 3.

That could be the difference between life and death for one of those kids.

Einstein's clock is exactly one minute behind mine and still ticking!